0.01x^2+3.3=5x

Solution for 0.01x^2+3.3=5x equation:

0.01x^2+3.3=5x

We move all terms to the left:

0.01x^2+3.3-(5x)=0

a = 0.01; b = -5; c = +3.3;
Δ = b2-4ac
Δ = -52-4·0.01·3.3
Δ = 24.868
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{24.868}}{2*0.01}=\frac{5-\sqrt{24.868}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{24.868}}{2*0.01}=\frac{5+\sqrt{24.868}}{0.02}
$